Boat Covers John Boat
by on Saturday, November 6th, 2010 | No Comments

help with this rate of job problems, please?
John can row your Boat 12 miles while leading David to cover 26 miles in your boat. If David boat travels 15 mph faster boat of John, then, is how quickly John paddling his boat?
Since distance = Rate x Time, you know you can rearrange these variables to obtain: time = distance / rate and we are given that in such cases would be the time) even (The same "time" with the reasons of distance rates. So let's set them equal to each other … is the distance / John 'John' David s rate = distance / rate of 12 David s / J = 26 / (15 J) Now cross multiply and solve … 26J = 12 (15 J) 12J + 26J = 180 = 180 = 12.86 mph 14J J
mark hogan john boat blues
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Advanced R/C Boat Modeling $65 Used – All you need to know to become a serious model powerboat racer. Author John Finch covers it all, from model set up to trimming. Read about monos, hydros, tunnels, cats and outriggers, plus engine function and rework, tuned-pipe theory, and hardware selection. This book is the best guide for model boat enthusiasts — sportsmen and competitors alike. |
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